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Q.

A circular ring has a diameter 10 cm and resistance 0.05 $Ω$ . The ring is placed in a uniform magnetic field of B = 0.5 T, initially, perpendicular to the field. The ring is then turned to a position parallel to the field in a time 0.1 sec. Charge that flows through the ring is nearly :

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a

100 mC

b

25 mC

c

125 mC

d

75 mC

answer is C.

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Detailed Solution

$F l u x l i n k e d w i t h t h e c o i l = n A B \cos φ i n i t i a l l y φ = 0^{0} a n d f i n a l l y φ = 90^{0} c h a n g e i n f l u x = n A B c h a r g e i n d u c e d = d q = \frac{d φ}{R} = \frac{n A B}{R} = \frac{π \times 25 \times 10^{- 4} \times 0.5}{0.05} \approx 75 m c$

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