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Q.

A circular ring has a diameter 10 cm and resistance 0.05 Ω. The ring is placed in a uniform magnetic field of B = 0.5 T, initially, perpendicular to the field. The ring is then turned to a position parallel to the field in a time 0.1 sec. Charge that flows through the ring is nearly :

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a

125 mC

b

100 mC

c

75 mC

d

25 mC

answer is C.

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Detailed Solution

Flux linked with the coil = nAB cosφ initially φ=00 and finally φ=900 change in flux=nAB charge induced =dq=dφR=nABR=π×25×10-4×0.50.05≈75mc

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