Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A circular ring of mass M and radius R and a spherical shell of mass 3M and radius R are arranged such that their centers are separated by a distance 3R and the plane of the circular ring is perpendicular to the line joining the centers. Gravitational field intensity at a point at a distance ‘R’ from the center of the ring is 

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

GMR234122towards the center of  spherical shell

b

GMR234+122towards the center of  circular ring

c

GM22R2towards the circular ring

d

GMR22+22towards the center of  spherical shell

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Question Image

Let P be the point of interest. Gravitational field at ‘P’ due to circular ring.
  E1=GMx(x2+R2)32  here x=distance of the point from center of the ring; R=radius of the ring E1=GMRR2+R23/2=GMR22R3=GM22R2
Gravitational field at ‘P’ due to spherical shell

  E2=3GM2R2=3GM4R2  

Net gravitational field at a point ‘P’ is 
Enet=E2E1   E2>E1  towards center of spherical shell.
Enet=3GM4R2GM22R2 
Enet=GMR234122 towards center of spherical shell.
 

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring