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A circular wire frame of radius R is dipped in a soap solution of surface tension $σ$ . When it is taken out a thin soap film is formed inside the frame. The force on the frame will be

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$8 πσR$

$πσR$

$4 πσR$

$2 πσR$

answer is C.

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Detailed Solution

Total length of wire is L = 2 $π$ R. Since the film is in air, force on frame = 2 $σ$ x L = $2 σ \times 2 π R = 4 π σ R$ .

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