A circus tent is cylindrical up to a height of 3 m and conical above it. If the diameter of the base is 105 m and the slant height of the conical part is 53 m, Then the total canvas used in making the tent is

Given, that height of cylinder $=3\mathrm{m}$

Diameter of base $=105\mathrm{m}$

Radius $=52.5\mathrm{m}$

Slant height of cone$=53\mathrm{m}$ 

Total canvas required $=$ curved surface area of cone $+$ curved surface area of cylinder

$=\pi rl+2\pi rh$

$=\frac{22}{7}(52.5\times 53+6\times 52.5)$

$=\frac{22}{7}\times 52.5\left(59\right)$

$=9735 {\mathrm{m}}^2$