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Q.

A clerk starts from his house with a speed of 2 kmh−1 and reaches the office 3 min late. Next day he increases speed 1 kmh−1 and reaches the office 3 min earlier. Find the distance between his house and office.

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a

2 km

b

1 km

c

0.6 km

d

3 km

answer is B.

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Detailed Solution

If distance between his house and office is s.
∴2=st+360 (for 1st event)  ……….. (i)
∴2+1=st−360   (for 2nd event)  ……….. (ii)
On solving Eqs. (i) and (ii), we get s=0.6 km  

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