Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5

Q.

A clock with a brass pendulum gains 1 minute per day in winter at a temperature of 20 °C. Another clock with a steel pendulum loses 1 minute per day in summer at a temperature 40 °C. The temperature at which the two clocks show correct time is (αBrass=18×10−6/oC; αsteel=12×10−6/oC)

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

28°C

b

27°C

c

25°C

d

30°C

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Explanation

The time gain or loss per day (Δt) due to temperature change can be approximated by:

Δt = (1/2) α ΔT × 86400 seconds

Brass Pendulum

  • Coefficient of Linear Expansion: αBrass = 18 × 10−6 °C−1
  • Time Gain: 1 minute/day = 60 seconds/day
  • Equation: 60 = (1/2) × 18 × 10−6 × (T − 20) × 86400
  • Solving for T: T ≈ 20.077 °C

Steel Pendulum

  • Coefficient of Linear Expansion: αSteel = 12 × 10−6 °C−1
  • Time Loss: 1 minute/day = 60 seconds/day
  • Equation: 60 = (1/2) × 12 × 10−6 × (40 − T) × 86400
  • Solving for T: T ≈ 39.885 °C

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon