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Q.

A clock with a brass pendulum gains 1 minute per day in winter at a temperature of 20 °C. Another clock with a steel pendulum loses 1 minute per day in summer at a temperature 40 °C. The temperature at which the two clocks show correct time is (αBrass=18×10−6/oC; αsteel=12×10−6/oC)

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a

28°C

b

27°C

c

25°C

d

30°C

answer is B.

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Detailed Solution

Explanation

The time gain or loss per day (Δt) due to temperature change can be approximated by:

Δt = (1/2) α ΔT × 86400 seconds

Brass Pendulum

  • Coefficient of Linear Expansion: αBrass = 18 × 10−6 °C−1
  • Time Gain: 1 minute/day = 60 seconds/day
  • Equation: 60 = (1/2) × 18 × 10−6 × (T − 20) × 86400
  • Solving for T: T ≈ 20.077 °C

Steel Pendulum

  • Coefficient of Linear Expansion: αSteel = 12 × 10−6 °C−1
  • Time Loss: 1 minute/day = 60 seconds/day
  • Equation: 60 = (1/2) × 12 × 10−6 × (40 − T) × 86400
  • Solving for T: T ≈ 39.885 °C
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