A clock with a brass pendulum keep correct time at 20°C but loses 8.212 s per day when the temperature rises to 30°C. The coefficient of linear expansion of brass is

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25 × 10^-6/°C

11 × 10^-6/°C

19 × 10^-6/°C

20 × 10^-6/°C

answer is B.

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Detailed Solution

t₁ = 20^oC, t₂ = 30^oC, $α$ = ?
loss in time per day $∆ T$ = 8.212 sec
we have
$∆ T = \frac{1}{2} α ∆ t (86400) 8.212 = \frac{1}{2} α (30 - 20) (86400) α = 19 x 10^{- 6} /^{o} C$

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