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A clock, with a brass pendulum, keeps correct time at $20^{0} C$ , but loses 8.64s per day, when the temperature rises to $30^{0} C$ . The coefficient of linear expansion of brass is___ $\times 10^{- 5}^{0} C^{- 1}$ .

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answer is 2.

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Detailed Solution

In case of metal pendulum clocks, loss or gain in time per day =
$\frac{1}{2} α Δ t \times 86400 \sec 8.64 = \frac{1}{2} \times α \times 10 \times 86400 α = 2 \times 10^{- 5}^{0} C^{- 1}$

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