Q.

A closed loop PQRS carrying a current is placed in a uniform magnetic field, If the magnetic forces on segments PS, SR, and RQ are F1, F2 and F3 respectively and are in the plane of the paper and along the directions shown, the force on the segment QP is

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a

F3F1F2

b

F3F12+F22

c

F3F12F22

d

F3-F1+F2

answer is B.

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Detailed Solution

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Fnet=0

Therefore, force on QP will be equal and opposite to sun of forces on other sides.

FPQ=F22+F3-F12

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A closed loop PQRS carrying a current is placed in a uniform magnetic field, If the magnetic forces on segments PS, SR, and RQ are F1, F2 and F3 respectively and are in the plane of the paper and along the directions shown, the force on the segment QP is