A closed loop $P Q R S$ carrying a current is placed in a uniform magnetic field. If the magnetic forces on segment $P S$ , $S R$ and $R Q$ are $F_{1}$ , $F_{2}$ and $F_{3}$ respectively and are in the plane of the paper and along the directions shown, the force on the segment $Q P$ is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

$\sqrt{{(F_{3} - F_{1})}^{2} + F_{2}^{2}}$

$\sqrt{{(F_{3} - F_{1})}^{2} - F_{2}^{2}}$

$F_{3} + F_{1} - F_{2}$

$F_{3} - F_{1} + F_{2}$

answer is D.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

If $F_{4}$ is the force on segment $Q P$ , then

$\vec{F_{1}} + \vec{F_{2}} + \vec{F_{3}} + \vec{F_{4}} = 0$

and $\vec{F_{4}} = - (\vec{F_{1}} + \vec{F_{2}} + \vec{F_{3}})$

or $F_{4} = \sqrt{{(F_{3} - F_{1})}^{2} + F_{2}^{2}}$

Watch 3-min video & get full concept clarity

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test