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A closed vessel contains helium and ozone at a pressure of P atm. The ratio of He and oxygen atoms is 1: 1. If helium is removed from the vessel, the pressure of the system will reduce to : (Assume constant temperature)

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0.5 P atm

0.25 P atm

0.33 P atm

0.75 P atm

answer is C.

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Detailed Solution

Let N be the number of atoms of mole He and oxygen

Mole of He = N

Mole of $O_{3} = \frac{N}{3}$

Total number of moles $= N + \frac{N}{3} = \frac{4 N}{3}$

Total pressure = P

Hence,

$p_{O_{3}} = X_{O_{3}} P = \frac{\frac{N}{3 P}}{\frac{4 N}{3}} = 0.25 P$

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