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A closely wound coil has a radius of $6.00 c m$ and carries a current of $2.50 A$ . How many turns must it have if, at a point on the coil axis $6.00 c m$ from the centre of the coil, the magnetic field is $6.39 \times 10^{- 4} T$ .

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answer is B.

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Detailed Solution

Apply $B = \frac{μ_{0} N i R^{2}}{2 {(R^{2} + x^{2})}^{\frac{3}{2}}}$

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