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A closely wound solenoid 80 cm long has 5 layers of windings of 400 turns each. The diameter of the solenoid is 1.8 cm. If the current carried is $8.0 A$ , the magnetic field near the centre of the solenoid is

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$0.08 T$

$0.025 T$

$0.008 T$

$0.25 T$

answer is B.

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Detailed Solution

As $l >> r$ , we can use $B = μ_{0} n I$

So, $B = 5 \times μ_{0} nl$

$\begin{array}{l} B = 5 \times 4 π \times 10^{- 7} \times \frac{400}{0.8} \times 8 = 80 π \times 10^{- 4} \\ = 0.025 T \end{array}$

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