A co-ordination complex has the formula ${PtCl}_{4} . 2 KCL$ Electrical conductance measurement indicate the presence of three ion in one formula unit. Treatment with ${AgNO}_{3}$ produces no precipitate of $AgCL$ What is the co-ordination number of Pt in this complex?

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answer is B.

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Detailed Solution

Since there are 6 ligands attached to the platinum. The co-ordination number of Pt in this complex is 6.

$\begin{array}{l} {PtCl}_{4} \cdot 2 KCl \equiv K_{2} [{PtCl}_{6}] ⇌ {Kq}^{+} + {[{PtCl}_{6}]}^{2 +} \\ K_{2} [{PtCl}_{6}] \to 2 K^{+} + [{PtCl}_{6}] \\ K_{2} [{PtCl}_{6}] + {AgNO}_{3} ⟶ No ppt \end{array}$

Hence correct option is B.

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