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Q.

A coil formed by wrapping 50 turns of wire in the shape of a square is positioned in a magnetic field so that the normal to the plane of the coil makes an angle of 30°   with the direction of the field. When the magnetic field is increased uniformly  from 200µT  to 600µ T  in 0.4 s, an emf of magnitude 80.0 V  is induced in the coil, the total length of the wire is  270+xm,​​​   then​     x=?

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answer is 2.

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Detailed Solution

 =272me=NΔϕΔt=NSΔBΔtcos30 S=eΔtNΔBsec30=80×103(0.4)(50)400×10623=1.85m
   Side of square  = 1.36m
Total length of wire   = 272m 
 

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