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A coil having an area ${2m}^{2}$ is placed in a magnetic field which changes from $1 W b / m^{2}$ to $4 W b / m^{2}$ in an interval of 2 seconds. The average e.m.f induced in the coil will be

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1.5V

answer is B.

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Detailed Solution

$A = 2 m^{2}, B_{1} = 1 w b / m^{2}, B_{2} = 4 w b / m^{2}, t = 2 s$

$e = \frac{- A (B_{2} - B_{1})}{t}$

$|e| = \frac{2 (4 - 1)}{2} = 3 V$

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