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A coil is placed in a transverse magnetic field of 0.02T. If this coil starts shrinking at a rate of 1mm/sec. While its radius remains 4 cm, then the value of induced emf is.

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$2 μ V$

$50 μ V$

$5 μ V$

$8 μ V$

answer is B.

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Detailed Solution

Here B=0.02T. $\frac{d r}{d t} = 1 m m / s = 10^{- 3} m / \sec$

$r = 4 c m = 4 \times 10^{- 2} m$ $e = ?$

$ϕ = B A = B (π r^{2})$

$e = \frac{d ϕ}{d t} = \frac{d (B π r^{2})}{d t} = B 2 π r \frac{d r}{d t}$

$e = 0.02 \times 2 \times \frac{22}{7} \times 4 \times 10^{- 2} \times 10^{- 3} = 5 \times 10^{- 6} V = 5 μ v$

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