A coil is placed perpendicular to a magnetic field of 5000T. When the field is changed to 3000T in 2s, an induced emf 22V is produced in the coil. If the diameter of the coil is 0.02m, then the number of turns in the coil is

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answer is 70.

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Detailed Solution

$ε = N (\frac{Δ ϕ}{t}) Δ ϕ = (Δ B) A B_{i} = 5000 T, B_{f} = 3000 T d = 0.02 m r = 0.01 m Δ ϕ = (Δ B) A = (2000) π {(0.01)}^{2} = 0.2 π ε = N (\frac{Δ ϕ}{t}) \Rightarrow 22 = N (\frac{0.02 π}{2}) N = 70$

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