A coil of 20 turns has an area of 800mm² and carries a current of 0.5A. If it is placed in magnetic field of intensity 0.3T with its plane parallel to the field, what is the torque that it experiences?

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Detailed Solution

$\begin{array}{l} τ = BiAn \cos θ \\ B = 0 .3 T, A = 800 \times 10^{- 6} m^{2} \\ i = 0 .5 A, n = 20, θ = 0^{\circ} \\ τ = 0 .3 \times 0 .5 \times 800 \times 10^{- 6} \times 20 \times \cos 0^{\circ} \\ τ = 2 .4 \times 10^{- 3} Nm \end{array}$

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