A coil of 200 turns and area $0.20m^2$ is rotated at half a revolution per second and is placed in uniform magnetic field of 0.1 T perpendicular to axis of rotation of the coil. The maximum voltage generated in the coil is

Given Data:

• N = 200 turns
• A = 0.20 m²
• B = 0.1 T
• The coil rotates at 0.5 revolutions per second.

Convert the rotational speed to angular velocity:

• Revolutions per second = 0.5 rev/s
• Radians per second = 0.5 × 2π = π rad/s

Now calculate the maximum emf:

Maximum emf = 200 × 0.20 × 0.1 × π = 4π × 0.1 = 0.4π V

Comparison with Options:

• a) 2π/3 volts
• b) 2π/5 volts
• c) π/5 volts
• d) π/10 volts

Since 0.4π = 2π/5, the correct answer is: b) 2π/5 volts