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Q.

A coil of a long solenoid having 800 turns per metre and magnetic intensity H at the center of solenoid is 2500 A m-1, then the current (in  A) passing in the coil is

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a

3.225 A

b

3.205 A

c

3.125 A

d

3.120 A

answer is A.

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Detailed Solution

As per question, H=2500 A m-1 and number of turns per unit length of a solenoid, n=800 m-1.

As per relation, H=n I, we have

I=Hn=2500800=3.125 A

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