A coil of area 5 square cm and 20 turns is placed in a uniform magnetic field of 103 gauss. The normal to the plane of the coil makes an angle of 60° with the magnetic field. The flux in maxwell through the coil is:

ϕ=NBAcosθ,N=20,B=103gauss,A=5 cm2, θ=600ϕ=20×103×5×cos600=5×104 maxwell

A coil of area 5 square cm and 20 turns is placed in a uniform magnetic field of 103 gauss. The normal to the plane of the coil makes an angle of 60° with the magnetic field. The flux in maxwell through the coil is:

ϕ=NBAcosθ,N=20,B=103gauss,A=5 cm2, θ=600ϕ=20×103×5×cos600=5×104 maxwell

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A coil of area 5 square cm and 20 turns is placed in a uniform magnetic field of 10³ gauss. The normal to the plane of the coil makes an angle of 60° with the magnetic field. The flux in maxwell through the coil is:

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10⁵

5 x 10⁴

2 x 10⁴

5 x 10³

answer is B.

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$\begin{array}{rcl} ϕ & = & NBAcosθ, \\ N & = & 20, \\ B & = & 10^{3} gauss, \\ A & = & 5 {cm}^{2}, \\ θ & = & 60^{0} \end{array}$

$ϕ = 20 \times 10^{3} \times 5 \times \cos 60^{0} = 5 \times 10^{4} maxwell$

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A coil of area 5 square cm and 20 turns is placed in a uniform magnetic field of 103 gauss. The normal to the plane of the coil makes an angle of 60° with the magnetic field. The flux in maxwell through the coil is:

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A coil of area 5 square cm and 20 turns is placed in a uniform magnetic field of 10³ gauss. The normal to the plane of the coil makes an angle of 60° with the magnetic field. The flux in maxwell through the coil is: