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A coil of area 500 cm² having 1000 turns is put perpendicular to a magnetic field of intensity 4 x 10^-5weber/m². If it is rotated by 180° in 0.1 s, the induced emf produced is :

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20 mV

80 mV

60 mV

40 mV

answer is B.

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Detailed Solution

Here change in flux due to 180⁰ rotation is nAB-(-nAB)=2nAB

induced emf = $i n d u c e d e m f = \frac{2 n A B}{t} = \frac{2 \times 1000 \times 5 \times 10^{- 2} \times 4 \times 10^{- 5}}{0.1} = 40 \times 10^{- 3} = 40 m V$

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