A coil of inductance 300mH and resistance 2 $Ω$ is connected to a source of voltage 2V. The current reaches half of its steady state value in $x \times 10^{- 2} \sec$ Then the value of x.

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Detailed Solution

During growth of current in the coil.
$i = i_{0} (1 - e^{- Rt / L}) For i = \frac{i_{0}}{2} \Rightarrow \frac{i_{0}}{2} = i_{0} (1 - e^{- Rt / L}) ∴ t = 0 .693 \frac{L}{R} = 0 .693 \times \frac{300 \times 10^{- 3}}{2} = 0 .1 s$

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