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Q.

A coil of inductance L=50μH and resistance=0.5Ω  is connected to a battery of emf=5V.A resistance of  10Ω is connected parallel to the coil. Now at some instant the connection of the battery is switched off. Then, the amount of heat generated in the coil after switching off the battery is  0.02x inmJ. Find value of x (to the nearest integer)

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answer is 6.

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Detailed Solution

 U=12Li 02=12×50×10650.52J=2.5mJ
Now, after switching off the battery this energy is dissipated in coil(resistance=0.5)and resistance10Ω in the ratio of their resistances H=i2Rt  orHR. Therefore, heat generated in the coil H=2.50.50.5+10mJ=0.12mJ
 

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