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A coil of resistance 10 ohm and inductance 5 henry is connected to a 100 volt battery. Then, the energy stored in the coil. In the form of magnetic field (In steady state)

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1000 J

250 J

125 J

750 J

answer is A.

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Detailed Solution

U = \frac{1}{2} L i^{2}

$U = \frac{1}{2} L \frac{v^{2}}{R^{2}} (i = \frac{v}{R})$

$= \frac{1}{2} \times 5 \times 100$

$U = 250 J$

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