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Q.

A coil of resistance 10 ohm and inductance 5 henry is connected to a 100 volt battery. Then, the energy stored in the coil in the form of magnetic field (In steady state) _____joules

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answer is 250.

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Detailed Solution

$I = \frac{V}{R} = \frac{100}{10} = 10 A Now, U = \frac{1}{2} {LI}^{2} = \frac{1}{2} \times 5 \times (10)^{2} = 250 J$

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