Q.

A coil of resistance 400 Ω is placed in a magnetic field. If the magnetic flux ϕ(wb) linked with the coil varies with-time t(sec) as ϕ=50t2+4. The current in the coil at t = 2 sec is :

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

0.5 A

b

0.1 A

c

2 A

d

1 A

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Given,

Coil resistance R= 400 Ω 

It is placed in magnetic field. 

Time t= 2 sec 

Magnetic flux,

ϕ=50t2+4

Here, the Induce emf ,

 ε=dϕdt=ddt50t2+4

=100t V

Thus, induce current in coil at 2 sec,

I=|ε|R I=200V400Ω I=12A I=0.5A

 

Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon