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Q.

A coil of resistance 400 Ω is placed in a magnetic field. If the magnetic flux ϕ(wb) linked with the coil varies with-time t(sec) as ϕ=50t2+4. The current in the coil at t = 2 sec is :

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a

0.5 A

b

1 A

c

2 A

d

0.1 A

answer is A.

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Detailed Solution

Given,

Coil resistance R= 400 Ω 

It is placed in magnetic field. 

Time t= 2 sec 

Magnetic flux,

ϕ=50t2+4

Here, the Induce emf ,

 ε=dϕdt=ddt50t2+4

=100t V

Thus, induce current in coil at 2 sec,

I=|ε|R I=200V400Ω I=12A I=0.5A

 

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