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Q.

A coil of self-inductance 40 mH and internal resistance 9Ω is used as a heater. It is connected to a source of alternating voltage of amplitude 300 V and angular frequency 300 rad/s and used to heat 2 kg of water placed in a vessel of heat capacity 3000 J/0C. The heat capacity of the coil is1200 J/0C Initially, the coil, the water and the vessel, all are at temperature 200C. Assuming that no heat is lost to the surroundings, and that the coil, the water and the vessel always remain at the same temperature, the time (in seconds) after which the temperature of the water has risen to 600C is ____________.(Specific heat of water =4200 J/kg0C)  

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answer is 280.

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Detailed Solution

Average power dissipated in the coil, P=V2R2Z2=V2R2(R2+(ωL)2)=(300)2(9)2(92+((300)(0.04))2)=1800W

Total heat needed to raise the temperature of the coil, the water and the vessel to 60  °C, H=(2(4200)+3000+1200)(6020)=504  kJ

Therefore, the time taken, t=Hp=504×1031800=280  s

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