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A coil with 200 turn and cross sectional area 0.10 m² is rotated at 30 rev / min and it is placed in a uniform magnetic field of 0.02 T perpendicular to the axis of rotation of the coil. The maximum voltage generated in the coil is

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2.16 V

4.12 V

1.26 V

3.24 V

answer is A.

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Detailed Solution

Here

$\begin{array}{l} v = 0 .5 Hz, N = 200, A = 0 .1 m^{2} \\ and B = 0 .02 T \\ ε_{0} = NBA (2 πv) = 200 \times 0 .02 \times 0 .1 \\ \times (2 π \times 0 .5) = 1 .26 V \end{array}$

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