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A coin is tossed 10 times with the frequencies: Head -4, Tail -6. The probability of number of heads is:

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\frac{5}{6}

\frac{4}{5}

\frac{2}{5}

\frac{3}{5}

answer is D.

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Detailed Solution

Given,

n S = 10

n H = 4

and

n T = 6

.
Number of no heads,

n N H = 6

, i.e., the number of tails is equal to the number of no heads.
Now, the probability of no heads, i.e.,

P N H

⇒ P (NH) = n (NH) n (S) ⇒ P (NH) = 610 ⇒ P (NH) = 35

So, probability of occurrence of no heads is

35

.
Hence, the correct option is 4.

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