A coin is tossed two times. Find the probability of getting at least one head.

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\frac{9}{4}

\frac{7}{4}

\frac{3}{4}

\frac{1}{4}

answer is C.

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Detailed Solution

Given, a coin is tossed two times.
The P(A) of the random experiment as,

P (A) = \frac{Number of favorable outcomes}{Total number of outcomes}

The total number of outcomes when a coin is tossed two times is 4.
n(S) = {HH,TT,TH,HT}
The number of events getting at least one head is 3.
n(X) = {HH,TH,HT}
So, the probability of getting at least one head is,

P (X) = \frac{n (X)}{n (S)}

\Rightarrow P (X) = \frac{3}{4}

The probability of getting at least one head is

\frac{3}{4}

.
Hence, option 3 is the correct answer.

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