A colloidal solution is subjected to an electrical field. The particles move towards anode. The coagulation of the same solution is studied using $NaCl,$ ${BaCl}_{2}$ and ${AlCl}_{3}$ solutions. Their coagulating power should be :

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$\begin{aligned} NaCl > {BaCl}_{2} > {AlCl}_{3} \end{aligned}$

${BaCl}_{2} > {AlCl}_{3} > {NaCl}^{}$

$\begin{aligned} {AlCl}_{3} > {BaCl}_{2} > NaCl \end{aligned}$

${BaCl}_{2} > NaCl > {AlCl}_{3}$

answer is C.

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Detailed Solution

When colloidal solution is exposed to electrical field, coagulating power should be in the order of ${AlCl}_{3} > {BaCl}_{2} > NaCl$ as their valency is rising.

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