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Q.

A colloidal solution is subjected to an electrical field. The particles move towards anode. The coagulation of same sol is studied using NaCl, BaCl2 and AlCl3 solutions. Their coagulating power should be

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a

NaCl > BaCl2 > AlCl3

b

BaCl2 > AlCl3 > NaCl

c

AlCl3 > BaCl2 > NaCl

d

BaCl2 > NaCl > AlCl3

answer is C.

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Detailed Solution

Sol particles are moving towards anode, sol is negatively charged

According to Hardy-Schulze rule, Greater the valency of flocculating ion (oppositely charged ion),

greater will be its coagulating power

For -ve sol

                  Coagulating power of  Al+3 > Ba+2 > Na+

therefore AlCl3 > BaCl2 > NaCl

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