A colloidal solution is subjected to an electrical field. The particles move towards anode. The coagulation of same sol is studied using NaCl, BaCl₂ and AlCl₃ solutions. Their coagulating power should be

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NaCl > BaCl₂ > AlCl₃

BaCl₂ > AlCl₃ > NaCl

AlCl₃ > BaCl₂ > NaCl

BaCl₂ > NaCl > AlCl₃

answer is C.

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Detailed Solution

Sol particles are moving towards anode, sol is negatively charged

According to Hardy-Schulze rule, Greater the valency of flocculating ion (oppositely charged ion),

greater will be its coagulating power

For -ve sol

Coagulating power of Al⁺³ > Ba⁺² > Na⁺

$therefore$ AlCl₃ > BaCl₂ > NaCl

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