A colorblind man marry with the daughter of a colorblind father, the generation will be 

1. As females have two X chromosomes, the daughter of a colorblind father will be a carrier for the trait, genotypically a heterozygous carrier, and phenotypically normal, if the male partner is colorblind. 
2. The female progeny will have a 1:1 ratio of Normal carriers. 
3. While the male offspring will be colorblind normal in a 1:1 ratio. The daughter of a color-blind father marries a color-blind man. Half of the generation will be colorblind. 
4. A color-blind person's daughter carries the illness because she carries recessive genes on one X chromosome. Half sons will be colorblind as a result.

Hence, option D is the correct answer.