A colourless salt (X) is soluble in water and also in alcohol and amines. On strong heating, (X) gives a brown gas (Y) and a grey residue. (X) dissolves in ammonia to give a solution (Z) which gives silver mirror with aldehydes. A solution of (X) is easily reduced by iron (II) sulphate. A solution of (X) also gives a brick red precipitate with potassium dichromate solution. Hence, choose the correct alternative:

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X - $Pb {({NO}_{3})}_{2} Y - {NO}_{2} Z - {Ag}_{2} O$

$X - {AgNO}_{3} Y - NO Z - {[Ag {({NH}_{3})}_{2}]}^{\oplus}$

$X - {AgNO}_{3} Y - {NO}_{2} Z - {Ag}_{2} O$

$X - {AgNO}_{3} Y - {NO}_{2} Z - {[Ag {({NH}_{3})}_{2}]}^{\oplus}$

answer is D.

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Detailed Solution

${AgNO}_{3} \overset{Δ}{⟶} 2 Ag ↓ + 2 {NO}_{2} ↑ + O_{2} ↑ (X) (Grey residue) (Y) {AgNO}_{3} + {NH}_{4} OH ⟶ {[Ag {({NH}_{3})}_{2}]}^{\oplus} 2 {[Ag {({NH}_{3})}_{2}]}^{\oplus} + {CH}_{3} CHO + H_{2} O ⟶ 2 Ag ↓ + {CH}_{3} {COO}^{⊖} + 3 {NH}_{4}^{\oplus} + {NH}_{3} {Ag}^{\oplus} + {Fe}^{2 +} ⟶ Ag ↓ + {Fe}^{3 +} 2 {AgNO}_{3} + K_{2} {CrO}_{4} ⟶ {Ag}_{2} {CrO}_{4} ↓ + 2 {KNO}_{3} (Brick red)$