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Q.

A combination of capacitors is set up as shown in the figure. The magnitude of the electric field due to a point charge Q(having a charge equal to the sum of the charges on the 4μF and 9μF capacitors), at a point distance 30m from it, would equal :

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a

360 N/C

b

420 N/C

c

480 N/C

d

240 N/C

answer is B.

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Detailed Solution

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Q1=24μCQ2=18μC Q3=42μC=Q1+Q2 E=107×42×10−6 E=kqr2 E=420N/C

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