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Q.

A commercially sold conc. $HCI$ is $35 % HCI$ by mass. If the density of this commercial acid is $1.46 g / mL$ , the molarity of this solution is :
(Atomic mass : $Cl = 35.5 amu, H = 1 amu$ )

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a

$12.5 M$

b

$14.0 M$

c

$10.2 M$

d

$18.2 M$

answer is C.

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Detailed Solution

Let total volume $= 1000 mL = 1 L$

The total mass of solution $= 1460 g$

mass of $HCl = \frac{35}{100} \times 1460$

moles of $HCl = \frac{35 \times 1460}{100 \times 36.5}$

So molarity $= \frac{35 \times 1460}{100 \times 36.5} = 14 M$

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