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Q.

A company dissolves ‘x’ amount of $C O_{2}$ at 298 K in 1 litre of water to prepare soda water.
$' x' =____\times 10^{- 3} g$ (nearest integer) (Given : Partial pressure of $C O_{2}$ at 298 K = 1.67 K bar, atomic mass of H, C and O is 1, 12 and 16 g/mole respectively)

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answer is 1221.

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Detailed Solution

According to Henry’s law

$P_{g a s} = K_{H} \times X_{g a s}$

$X_{g a s} = \frac{m o l e s o f g a s}{T o t a l m o l e s} = \frac{n C o_{2}}{n C o_{2} + n H_{2} O}$

$n H_{2} O = \frac{1000}{18} = 55.5$

$X C o_{2} = \frac{n C o_{2}}{n C o_{2} + 55.5} = \frac{P C o_{2}}{K_{H}}$

$= \frac{0.835}{1.67 \times 10^{3}} = 0.5 \times 10^{- 3}$

$\frac{n C o_{2}}{55.5} = 0.5 \times 10^{- 3} (∴ 55.5 > > > n C o_{2})$

$n C o_{2} = 0.5 \times 10^{- 3} \times 55.5 = 27.75 \times 10^{- 3}$

Mass of $C o_{2} = 27.75 \times 10^{- 3} \times 44 = 1221 \times 10^{- 3} g$

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A company dissolves ‘x’ amount of CO2 at 298 K in 1 litre of water to prepare soda water.'x'=____×10−3g (nearest integer) (Given : Partial pressure of CO2 at 298 K = 1.67 K bar, atomic mass of H, C and O is 1, 12 and 16 g/mole respectively)