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Q.

A compass needle whose magnetic moment is 60 Am2, is directed towards geographical north at any place experiencing a moment of force of 1.2 × 10-3 Nm. At that place, the horizontal component of the earth field is 40 micro W/m2. What is the value of the dip angle at that place?

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a

45°

b

60°

c

30°

d

15°

answer is A.

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Detailed Solution

M = 6 0Am2 ζ¯ =1.2 ×10-3Nm, BH = 40×10-6 Wb/m2 ζ = M  × BH    ζ = MBH Sinθ 1.2 × 10-3 =60 × 40 × 10-6 sinθ  sinθ =1.2 ×10-360× 40×10-6=12=sin 30°  θ=30°   

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