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Q.

A complex compound of iron has molar mass $= 2800$ and it contains 8% iron by weight. The number of iron atoms in one formula unit of complex compound is:

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answer is 4.

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Detailed Solution

Percentage mass of an Fe

$= \frac{(No. of atoms of Fe) \times (At. mass of Fe) \times 100}{Molecular mass of substance}$

$8 = \frac{x \times 56}{2800} \times 100 \Rightarrow x = 4$

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