A complex of platinum, ammonia and chloride produces four ions per molecule in the solution. The structure consistent with the observation is :

$\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_4\right]{\mathrm{Cl}}_4$ Complex ion + 4 Cl ion = 5 ion

$\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_2{\mathrm{Cl}}_4\right]$ no ion (doesn’t dissociate into ions)

$\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_5{\mathrm{Cl}}_3{\mathrm{Cl}}_3\right.$ Complex ion + 3 Cl ion = 4 ions.

$\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_4{\mathrm{Cl}}_2\right]{\mathrm{Cl}}_2$ (Complex ion + 2 Cl ions) 3 ions.

So, the option C is correct