A composite parallel plate capacitor is made up of two different dielectric materials with different thickness (t1 and t2) as shown in figure. The two different dielectric materials are separated by a conducting foil F. The voltage of the conducting foil is ___V.

C1C2=3×t2t1×4=32qC1=v1,qC2=v2v1v2=C2C1=23v1+v2=100So, the voltage of foil is 100-40=60V

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A composite parallel plate capacitor is made up of two different dielectric materials with different thickness (t₁ and t₂) as shown in figure. The two different dielectric materials are separated by a conducting foil F. The voltage of the conducting foil is ___V.

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answer is 60.

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Detailed Solution

$\begin{aligned} \frac{C_{1}}{C_{2}} = \frac{3 \times t_{2}}{t_{1} \times 4} = \frac{3}{2} \\ \frac{q}{C_{1}} = v_{1}, \frac{q}{C_{2}} = v_{2} \\ \frac{v_{1}}{v_{2}} = \frac{C_{2}}{C_{1}} = \frac{2}{3} \end{aligned}$

$v_{1} + v_{2} = 100$

So, the voltage of foil is 100-40=60V

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