A compound 'A' on reaction with 'X' and 'Y produces the same major product but different by product 'a' and 'b'. Oxidation of 'a’ gives a substance produced by ants.
‘X’ and ‘Y’ respectively are :

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KMnO₄/H⁺ and dil. KMnO₄, 273 K

KMnO₄,(dilute), 273 K and KMnO₄/H⁺

KMnO₄/H⁺ and O₃, H₂O/Zn

O₃, H₂O/Zn and KMnO₄/H⁺

answer is D.

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Detailed Solution

Chemistry Problem: Identify X and Y

CH₂=C-CH₂-C(CH₃)₂-CH₃
| |
CH₃ CH₃
Compound 'A'

With X:
a + O=C-CH₂-C(CH₃)₂-CH₃
|
CH₃

With Y:
b + O=C-CH₂-C(CH₃)₂-CH₃
|
CH₃

Clue: Oxidation of 'a' gives a substance produced by ants (formic acid, HCOOH).

Analysis

Product 'a', upon oxidation, gives formic acid, indicating 'a' is formaldehyde (HCHO).
Oxidative cleavage reagents:
- Ozonolysis (X = O₃) gives aldehydes (here, HCHO and the main ketone product).
- Hot KMnO₄ (Y = hot KMnO₄) gives acids (here, formic acid and the main ketone product).

Therefore,X = Ozonolysis, Y = Hot KMnO₄