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A compound AB forms $N a C l$ crystal structure and compound $' x y'$ forms $C s C l$ structure. The mass of $x y$ is three times that of $' A B'$ but the cubic edge of $' A B'$ is twice that of $x y$ . What is the ratio of densities of $' x y'$ to $A B$ .

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answer is 6.

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Detailed Solution

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$\frac{D_{xy}}{D_{AB}} = \frac{\frac{1 \times Mass of xy}{Na \times {(edgelength of xy)}^{3}}}{\frac{4 \times Mass of AB}{NA \times {(edge length of AB)}^{3}}} = \frac{\frac{1 \times 3 \times M_{AB}}{{(edge length of xy)}^{3}}}{\frac{4 \times mass of AB}{{(2 \times edge length of xy)}^{3}}} = \frac{3 \times 8}{4} = 6 : 1$

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A compound AB forms NaCl crystal structure and compound 'xy' forms CsCl structure. The mass of xy is three times that of 'AB' but the cubic edge of 'AB' is twice that of xy . What is the ratio of densities of 'xy' to AB.