A compound contains 69.5% oxygen, 30.5% nitrogen and its molecular weight is 92. The formula of compound is

$\text{ Empirical formula }={\mathrm{NO}}_2$

Empirical formula weight = 46

                             $\mathrm{n}=\frac{92}{46}=2$

$\Rightarrow \text{ Molecular formula }={\left({\mathrm{NO}}_2\right)}_2={\mathrm{N}}_2{\mathrm{O}}_4$