A compound contains atoms of three elements A, B and C. If the oxidation number of A is +2, B is +5 and that of C is –2, the possible formula of the compound is

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$A_{3} {({BC}_{4})}_{2}$

$A_{3} {(B_{4} C)}_{2}$

${ABC}_{2}$

$A_{2} {({BC}_{3})}_{2}$

answer is A.

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Detailed Solution

The formula of a compound with elements A, B, C will be of the form A_xB_yC_z, where x,y,z are the atomicities of individual atoms .

The oxidation numbers of the elements, A, B, C are +2,+5 and −2 respectively.
A compound is always neutral, so the oxidation number of the compound is zero. Hence, the net oxidation number of the individual atoms is zero.
(+2)(x)+(+5)(y)+(−2)(z)=0;2x+5y−2z=0.

Restricting it to conditions that maximum oxidation state could be +8 or −3, by Hit and Trial method, the possible solutions of (x,y,z) could be (1,2,6) or (3,2,8).

Both the sets are possible as the elements are unknown.

Hence the compounds are A(BC₃)₂ or A₃B₂C₈

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