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Q.

A compound contains 38.8%C, 16.0%H and 45.2% N. The formula of the compound would be

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a

CH3CN

b

C2H5CN

c

CH3NH2

d

CH2(CN)2

answer is A.

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Detailed Solution

ElementCHN
mass38.81645.2
no. of atoms38.8/12=3.2316/1=1645.2/14=3.22
relative no.of atoms3.23/3.22=116/3.22=53.22/3.22=1

So, the formula of the compound is CNH5⟶CH3NH2.

Therefore, option A is correct.

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