A compound has a cubical arrangement and it consist of atoms of P, Q and R.P atoms are present at the corners, Q atoms occupy face center position and R occupy alternate tetrahederal void as well as all octahedral void. If all the atoms lying on any one body diagonal are missing, then what would be the formula?

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$P Q_{4} R_{8}$

$P Q_{3} R_{8}$

$P_{3} Q_{12} R_{20}$

$P_{3} Q_{12} R_{32}$

answer is B.

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Detailed Solution

$p - 8 - 2 = 6 \times \frac{1}{8} = 3 / 4$

$a - 6 \times \frac{1}{2} = 3$

$R - 4 + 4 = 8 - 1 - 1 = 6$

fcc unit cell $3 / 4 : 3 : 6$

$1 : 4 : 8$

$P Q_{4} R_{8}$

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