A compound has the empirical formula C₁₀H₈Fe. A solution of 0.26 g of the compound in 11.2 g of benzene (C₆H₆) boils at 80.26^oC. The boiling point of benzene is 80.10^oC; the K_b is 2.53^oC/molal. What is the molecular formula of the compound?

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C₃₀H₂₄Fe₃

C₅H₄Fe

C₂₀H₁₆Fe₂

C₁₀H₈Fe

answer is D.

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Detailed Solution

$\begin{array}{l} T_{b} = 80 .26, {ΔT}_{b} = 0 .16 \\ 0 .16 = 2 .53 \times \frac{0 .26 / M}{11 .20} \times 1000; M \approx 367 \end{array}$
that is almost molar mass of C₂₀H₁₆Fe_2.

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